LEARN MATH STEP BY STEP THROUGH VERY EASY PROCESS

DIVISION WITH REGROUPING

__DIVISION WITH REGROUPING__

**Q.1) Find the Answer (Quotient) 72 ÷ 6 = ?**

**In this division you
can see that, by table of 6 you can’t reach to dividend, i.e 72. Dividend
must be divided by divisor separately. So,**

**Step.1****) **** Write the dividend and ****divisor**** as
shown 6 ) 7 2 (**

**Step.2****) Take the first digit from the
left of the Dividend which is 7. From the multiplication table of 6 we can
observe that , 1 X 6 = 6 , 2 X 6 = 12 , 3 X 6 = 18,…….. Product 6
only which is 6 < 7 , but next other product like 12 , 18 ,….. all > 7 ,
so we can’t subtract these number from 7 other than 6. So, write 6 at
‘Tens’ column below 7, write 1 as Quotient at the ‘Tens’ place and then
subtract 6 from 7, 7 – 6 = 1, here 1 Tens is the remainder.**

**Step.3****) Now take next digit 2 of the
dividend and write at the right side of 1(remainder) in the ones place and now
you have 12 ‘Ones’. Now you have to recall the table of 6 again and you
can find that 6 X 2 = 12. Write 2 in the ‘Ones’ place in the Quotient and
the product 12 under 12 and subtract. There is '0' Remainder and '12' is
Quotient.**

**
**

**
So,
Quotient 12 is the answer.**

**Q.2) Find the Answer (Quotient) 324 ÷ 3 = ?**

**In this division you
can see that, by table of 3 you can’t reach to dividend, i.e 325 at a
time. Dividend must be divided by divisor separately. So,**

**Step.1****) Write the dividend and
divisor as shown 3 ) 3 2 4 (**

**Step.2****) Take the first digit from the
left of the Dividend which is 3. From the multiplication table of 3 we can
observe that, 1 X 3 = 3 , 2 X 3 = 6 , 3 X 3 = 9,……..Product 3 only which is 3
<= 3 , but next other product like 6 , 9 ,….. all > 3 , so we can’t
subtract these number from 3 other than 3. So, write 3 at
‘Hundreds’ column below 3, write 1 as Quotient at the ‘Hundreds’ place and
then subtract 3 from 3, 3 – 3 = 0 , here 0 Tens is the remainder.**

**Step.3****) Now take next digit 2 of the
dividend and write at the right side of 0 (remainder) in the Ones
place and now you have 2 ‘Tens’ at the ‘Ones’ place. Now you have to recall the
table of 3 again and you can find that 3X1= 3, 3X2 = 6,…..we can’t divide 2 by
any of the obtained product even 3 itself , so we write 0 in the ‘Tens’
place in the Quotient, now change 2
‘Tens’ into 20 ‘Ones’ and bring 4 ‘Ones’ down from ‘Dividend’ and add with 20
‘Ones’ and make a new dividend 24 ‘ Ones’. Now we will recall again table Of 3
and we can find 3 X 8 = 24 , Write 8 in the ‘Ones’ place in the Quotient and
the product 24 under 24 and subtract. There is 0 remainder and 108 is the
Quotient. **

**
So, Quotient 108 is the
answer..**

**Q. 3) Find the Answer (Quotient) 210 ÷ 6 = ?**

**In this division you
can see that, by table of 6 you can’t reach to dividend, i.e 210 at a
time. Dividend must be divided by divisor separately. So,**

**Step.1****) Write the dividend and divisor
as shown 6 ) 2 1 0 (**

**Step.2****) Take the first digit from the
left of the Dividend which is 2. From the multiplication table of 6 we can
observe that, 1 X 6 = 6 , 2 X 6 = 12 , 3 X 6 = 18,…….. ****Product 6 and other
product also > 2, so in the ‘Hundreds’ place in the
quotient is empty or 0 as the dividend
2 ‘Hundreds’ can’t be divided by Divisor 6. We will change 2 ‘Hundreds’ to 20 ‘Tens’. So, we will take 1 ‘Ten’
and 2 ‘Hundreds’/ 20 ‘Tens’ together from dividend and consider it as 21 ‘Tens’,
and now recall the table of 6 . Write 18 (obtained from 3 X 6 = 18) , at
‘Tens’ column below 21, write 3 as Quotient at the ‘Tens’ place and then
subtract 18 from 21, 21 – 18 = 3 , here 3 Tens is the remainder.**

**Step.3****) Now take next digit 0 of the
dividend and bring down at the right side of 3 (remainder) in the ‘ones’ place
to make a new dividend and now you have 30 ‘Ones’. ****Now you
have to recall the table of 6 again and you can find that ……6X4= 24, 6X5
= ****30,.…….., so we write 5 in the ‘Ones’ place in the**** Quotient and the product 30 under 30 and
subtract. There is 0 remainder and 35 is the Quotient.**

**
So, Quotient 35 is the answer.**

**Q. 4) Find the Answer (Quotient) 9232 ÷ 4 = ?**

**In this division you
can see that, by table of 4 you can’t reach to dividend, i.e 9232 at a
time. Dividend must be divided by divisor separately. So,**

**Step.1****) Write the dividend and devisor
as shown 4 ) 9 2 3 2 (**

**Step.2****) Take the first digit from the
left of the Dividend which is 9. From the multiplication table of 4 we can
observe that, 1 X 4 = 4 , 2 X 4 = 8 , 3 X 4 = 12,……..****Product 8 only which
is 8 < 9 , but next other product like 12 , 16 ,….. all > 9 , so we
can’t subtract these number from 9 other than 8. So, write 8 at
‘Thousands’ column below 9, write 2 as Quotient at the ‘Thousands’ place
and then subtract 8 from 9, 9 – 8 = 1 , here 1 ‘Thousand’ is the
remainder.**

**Step.3****) Now take next digit 2 of the
dividend and write at the right side of 1 (remainder) in the
Hundreds place and now you have 12 ‘Hundreds’ as dividend. Now we have to recall the
table of 4 again and you can find that 4X2= 8, 4X3 = 12,…. . we will write 3 in the ‘Hundreds’ place of quotient and
place the product 12 under 12 and Subtract. There is 0 remainder. **

**Step.4****) Now we will bring down 3 ‘Tens’, but
we can’t divide 3 by 4 because 4 > 3, So,
write 0 in the ‘Tens’ place in the quotient and change from 3 ‘Tens’ to 30
‘Ones’, now bring 2 ‘Ones’ down and add to make new dividend 32
‘Ones’. We have to recall the table of 4 again and we can find that
…..4x7=28 , 4x8 =32, 4 X 9 =36,……… we will write 8 in the ‘Ones’ place of
quotient and place the product ****32 under 32 and subtract. There is 0
remainder and 2308 is the quotient.**

**
So, the answer is 2308.**

**Q. 5) Find the Answer (Quotient) 50 ÷ 3 = ?**

**In this division you
can see that, by table of 3 you can’t reach to dividend, i.e 50. Dividend
must be divided by divisor separately. So, **

**Step.1****) Write the dividend and
divisor as shown 3 ) 5 0 (**

**Step.2****) Take the first digit from the
left of the Dividend which is 5. From the multiplication table of 3 we can
observe that, 1 X 3 = 3 , 2 X 3 = 6 , 3 X 3 = 9,…….. Product 3 only which
is 3 < 5 , but next other product like 6 , 9 ,….. all > 5 , so we
can’t subtract these number from 5 other than 3. So, write 3 at ‘Tens’
column below 5, write 1 as Quotient at the ‘Tens’ place and then subtract
3 from 5, 5 – 3 = 2 , here 2 Tens is the remainder. **

**Step.3****) Now take next digit 0 of the
dividend and write at the right side of 2 (remainder) in the ones
place and now you have 20 ‘Ones’. Now you have to recall the table of 3
again like ……3x5=15, 3x6 =18, 3x7 =21, 3x8 =24,…………..and you can place 3 X 6 =
18. But you can’t place 3 x 7 = 21 because 18< 20, But 21 > 20 , so
write 6 in the ‘Ones’ place of Quotient and place the product 18
under 20 and subtract. There is 2 remainder and 16 is Quotient.**

**
So, 16 is the Quotient and 2 is the Remainder.**