# CLASS-2LINEAR SUBTRACTION WITH NUMBER WITHOUT TENS OR ONES

LINEAR SUBTRACTION OF TWO OR THREE DIGIT NUMBER WITHOUT TENS OR ONES

c)  20 =  2 Tens + 0 One = 2 Tens

d)   7 =  0 Ten + 7 Ones = 7 Ones

Q.1)   38 Ones - 05 Ones =  ?

3 Tens + 8 Ones – 0 Ten - 5 Ones

=  3 Tens - 0 Ten + 8 Ones - 5 Ones.  Step.1 – Subtr ‘Ones’

=   3 Tens - 0 Ten  + 3 Ones                     Step.2 – Subtr ‘Tens’

= 3 Tens + 3 Ones =  33        (Ans.)

Q.2)  7 Tens - 28 Ones = ?

Ans.)     7 Tens - 28 Ones

=  7 Tens + 0 Ones – 2 Tens – 8 Ones

In above, we have to subtract 8 Ones from 0 Ones, which is not possible, so we will place 1 before 0 One and will consider 10 Ones. Now, to balance we will subtract 1 Tens from 7 Tens, and we find 7 Tens – 1 Ten = 6 Tens. So, 7 Tens = 7 Tens + 0 One = 6 Tens + 10 Ones.

= 6 Tens + 10 Ones - 2 Tens - 8 Ones  Step.1 – Subtr. ‘Ones’

=  6 Tens – 2 Tens + 10 Ones – 8 Ones

= 6 Tens – 2 Tens + 2 Ones              Step.2 – Subtr. ‘Tens’

= 4 Tens + 2 Ones  =  42     (Ans.

Q.3)  8 Tens - 43 Ones = ?

8 Tens - 43 Ones

=  8 Tens + 0 Ones - 4 Tens - 3 Ones

In above, we have to subtract 3 Ones from 0 Ones, which is not possible, so we will place 1 before 0 One and will consider 10 Ones. Now, to balance we will subtract 1 Tens from 8 Tens, and we find 8 Tens – 1 Ten = 7 Tens. So, 8 Tens = 8 Tens + 0 One = 7 Tens + 10 Ones.

=  7 Tens + 10 Ones - 4 Tens - 3 Ones   Step.1 – Subtr.‘Ones’

=  7 Tens – 4 Tens + 7 Ones                        Step.2 – Subtr.‘Tens’

=  3 Tens + 7 Ones  =  37      (Ans.

Q.4)   9 Tens - 52 Ones = ?

9 Tens - 52 Tens

=  9 Tens + O One - 5 Tens - 2 One

In above, we have to subtract 2 Ones from 0 Ones, which is not possible, so we will place 1 before 0 One and will consider 10 Ones. Now, to balance we will subtract 1 Tens from 9 Tens, and we find 9 Tens – 1 Ten = 8 Tens. So, 9 Tens = 9 Tens + 0 One = 8 Tens + 10 Ones.

=  8 Tens + 1O Ones - 5 Tens - 2 Ones   Step.1 – Subtr. ‘Ones’

=  8 Tens – 5 Tens + 8 Ones                Step.2 – Subtr. ‘Tens’

=  3 Tens + 8 Ones =  38 Ones  =  38    (Ans.

Q.5)  35 Tens - 24 Ones = ?

35 Tens - 24 Ones

=  3 Hundreds + 5 Tens + 0 One - 2 Tens - 4 Ones

In above, we have to subtract 4 Ones from 0 Ones, which is not possible, so we will place 1 before 0 One and will consider 10 Ones. Now, to balance we will subtract 1 Tens from 5 Tens, and we find 5 Tens – 1 Ten = 4 Tens. So, 35 Tens = 3 Hundreds + 5 Tens + 0 One = 3 Hundreds + 4 Tens + 10 Ones.

= 3 Hundreds + 4 Tens + 10 Ones - 2 Tens - 4 Ones Step.1– Subtr.‘Ones’

= 3 Hundreds + 4 Tens + 6 Ones - 2 Tens            Step.2 – Subtr ‘Tens’

= 3 Hundreds + 2 Tens + 6 Ones  =  326 Ones =  326   (Ans.)

Q.6)  305 Ones - 35 Ones = ?

305 Ones - 35 Ones

=  3 Hundreds + 0 Ten + 5 Ones – 0 Hundred - 3 Tens - 5 Ones

In above, we have to subtract 3 Tens from 0 Ten, which is not possible, so we will place 1 before 0 Ten and will consider 10 Tens. Now, to balance we will subtract 1 Hundred from 3 Hundreds, and we find 3 Hundreds – 1 Hundred = 2 Hundreds. So, 305 Ones = 3 Hundreds + 0 Ten + 5 Ones = 2 Hundreds + 10 Tens + 5 Ones.

=  2 Hundreds + 10 Tens + 5 Ones – 0 Hundred - 3 Tens - 5 Ones                                                           Step.1 – Subtr. ‘Ones’

= 2 Hundreds + 10 Tens + 0 One – 0 Hundred - 3 Tens  Step.2 – Subtr ‘Tens’

= 2 Hundreds – 0 Hundred + 7 Tens + 0 One  Step.3 – Subtr ‘Hundreds’

= 2 Hundreds + 7 Tens + 0 One

= 270 Ones =  270   (Ans.