LINEAR SUBTRACTION OF TWO OR THREE DIGIT NUMBER WITHOUT TENS OR ONES
c) 20 = 2 Tens + 0 One = 2 Tens
d) 7 = 0 Ten + 7 Ones = 7 Ones
Q.1) 38 Ones - 05 Ones = ?
3 Tens + 8 Ones – 0 Ten - 5 Ones
= 3 Tens - 0 Ten + 8 Ones - 5 Ones. Step.1 – Subtr ‘Ones’
= 3 Tens - 0 Ten + 3 Ones Step.2 – Subtr ‘Tens’
= 3 Tens + 3 Ones = 33 (Ans.)
Q.2) 7 Tens - 28 Ones = ?
Ans.) 7 Tens - 28 Ones
= 7 Tens + 0 Ones – 2 Tens – 8 Ones
In above, we have to subtract 8 Ones from 0 Ones, which is not possible, so we will place 1 before 0 One and will consider 10 Ones. Now, to balance we will subtract 1 Tens from 7 Tens, and we find 7 Tens – 1 Ten = 6 Tens. So, 7 Tens = 7 Tens + 0 One = 6 Tens + 10 Ones.
= 6 Tens + 10 Ones - 2 Tens - 8 Ones Step.1 – Subtr. ‘Ones’
= 6 Tens – 2 Tens + 10 Ones – 8 Ones
= 6 Tens – 2 Tens + 2 Ones Step.2 – Subtr. ‘Tens’
= 4 Tens + 2 Ones = 42 (Ans.)
Q.3) 8 Tens - 43 Ones = ?
8 Tens - 43 Ones
= 8 Tens + 0 Ones - 4 Tens - 3 Ones
In above, we have to subtract 3 Ones from 0 Ones, which is not possible, so we will place 1 before 0 One and will consider 10 Ones. Now, to balance we will subtract 1 Tens from 8 Tens, and we find 8 Tens – 1 Ten = 7 Tens. So, 8 Tens = 8 Tens + 0 One = 7 Tens + 10 Ones.
= 7 Tens + 10 Ones - 4 Tens - 3 Ones Step.1 – Subtr.‘Ones’
= 7 Tens – 4 Tens + 7 Ones Step.2 – Subtr.‘Tens’
= 3 Tens + 7 Ones = 37 (Ans.)
Q.4) 9 Tens - 52 Ones = ?
9 Tens - 52 Tens
= 9 Tens + O One - 5 Tens - 2 One
In above, we have to subtract 2 Ones from 0 Ones, which is not possible, so we will place 1 before 0 One and will consider 10 Ones. Now, to balance we will subtract 1 Tens from 9 Tens, and we find 9 Tens – 1 Ten = 8 Tens. So, 9 Tens = 9 Tens + 0 One = 8 Tens + 10 Ones.
= 8 Tens + 1O Ones - 5 Tens - 2 Ones Step.1 – Subtr. ‘Ones’
= 8 Tens – 5 Tens + 8 Ones Step.2 – Subtr. ‘Tens’
= 3 Tens + 8 Ones = 38 Ones = 38 (Ans.)
Q.5) 35 Tens - 24 Ones = ?
35 Tens - 24 Ones
= 3 Hundreds + 5 Tens + 0 One - 2 Tens - 4 Ones
In above, we have to subtract 4 Ones from 0 Ones, which is not possible, so we will place 1 before 0 One and will consider 10 Ones. Now, to balance we will subtract 1 Tens from 5 Tens, and we find 5 Tens – 1 Ten = 4 Tens. So, 35 Tens = 3 Hundreds + 5 Tens + 0 One = 3 Hundreds + 4 Tens + 10 Ones.
= 3 Hundreds + 4 Tens + 10 Ones - 2 Tens - 4 Ones Step.1– Subtr.‘Ones’
= 3 Hundreds + 4 Tens + 6 Ones - 2 Tens Step.2 – Subtr ‘Tens’
= 3 Hundreds + 2 Tens + 6 Ones = 326 Ones = 326 (Ans.)
Q.6) 305 Ones - 35 Ones = ?
305 Ones - 35 Ones
= 3 Hundreds + 0 Ten + 5 Ones – 0 Hundred - 3 Tens - 5 Ones
In above, we have to subtract 3 Tens from 0 Ten, which is not possible, so we will place 1 before 0 Ten and will consider 10 Tens. Now, to balance we will subtract 1 Hundred from 3 Hundreds, and we find 3 Hundreds – 1 Hundred = 2 Hundreds. So, 305 Ones = 3 Hundreds + 0 Ten + 5 Ones = 2 Hundreds + 10 Tens + 5 Ones.
= 2 Hundreds + 10 Tens + 5 Ones – 0 Hundred - 3 Tens - 5 Ones Step.1 – Subtr. ‘Ones’
= 2 Hundreds + 10 Tens + 0 One – 0 Hundred - 3 Tens Step.2 – Subtr ‘Tens’
= 2 Hundreds – 0 Hundred + 7 Tens + 0 One Step.3 – Subtr ‘Hundreds’
= 2 Hundreds + 7 Tens + 0 One
= 270 Ones = 270 (Ans.)